3-1.Vectors
hard

The resultant of two vectors $\vec{A}$ and $\vec{B}$ is perpendicular to $\overrightarrow{\mathrm{A}}$ and its magnitude is half that of $\vec{B}$. The angle between vectors $\vec{A}$ and $\vec{B}$ is . . . . . . 

A$100$
B$110$
C$150$
D$160$
(JEE MAIN-2024)

Solution

$ B \cos \theta=\frac{B}{2}$
$\Rightarrow \theta=60^{\circ}$
So, angle between $\overrightarrow{\mathrm{A}} \& \overrightarrow{\mathrm{B}}$ is $90^{\circ}+60^{\circ}=150^{\circ}$
Standard 11
Physics

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