The same retarding force is applied to stop a train. The train stops after $80\, m$. If the speed is doubled, then the stopping distance will be
The same retarding force is applied to stop a train. The train stops after $80\, m$. If the speed is doubled, then the stopping distance will be
- A
The same
- B
Doubled
- C
Halved
- D
Four times
Similar Questions
The displacement and the increase in the velocity of a moving particle in the time interval of $t$ to $(t+1) \mathrm{s}$ are $125 \mathrm{~m}$ and $50 \mathrm{~m} / \mathrm{s}$, respectively. The distance travelled by the particle in $(\mathrm{t}+2)^{\mathrm{th}} \mathrm{s}$ is__________ $\mathrm{m}$.
- [JEE MAIN 2024]
A lift performs the first part of its ascent with uniform acceleration $a$ and the remaining with uniform retardation $2a$. If $t$ is the time of ascent, find the depth of the shaft.
A lift performs the first part of its ascent with uniform acceleration $a$ and the remaining with uniform retardation $2a$. If $t$ is the time of ascent, find the depth of the shaft.
A body starts from rest with uniform acceleration $a,$ its velocity after $n\,seconds$ is $v$. The displacement of the body in last $3\,s$ is : (assume total time of journey from $0$ to $n\,seconds$ )
A body starts from rest with uniform acceleration $a,$ its velocity after $n\,seconds$ is $v$. The displacement of the body in last $3\,s$ is : (assume total time of journey from $0$ to $n\,seconds$ )
What is the relation between displacement, time and acceleration in case of a body having uniform acceleration
What is the relation between displacement, time and acceleration in case of a body having uniform acceleration
Obtain equations of motion for constant acceleration using method of calculus.
Obtain equations of motion for constant acceleration using method of calculus.