8. Introduction to Trigonometry
easy

The simplification of $\frac{\cos (90- A ) \sin (90- A )}{\tan (90- A )}$ is .......

A

$\sin ^{2} A$

B

$\cos ^{2} A$

C

$\sin A$

D

$1$

Solution

$\frac{\cos (90- A ) \sin (90- A )}{\tan (90- A )}=\frac{\sin A \cos A }{\cot A }=\frac{\sin A \cos A }{\cos A / \sin A }=\sin ^{2} A$

Standard 10
Mathematics

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