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8. Introduction to Trigonometry
easy
The simplification of $\frac{\cos (90- A ) \sin (90- A )}{\tan (90- A )}$ is .......
A
$\sin ^{2} A$
B
$\cos ^{2} A$
C
$\sin A$
D
$1$
Solution
$\frac{\cos (90- A ) \sin (90- A )}{\tan (90- A )}=\frac{\sin A \cos A }{\cot A }=\frac{\sin A \cos A }{\cos A / \sin A }=\sin ^{2} A$
Standard 10
Mathematics