Solubility product of Mg{(OH)₂} is 1.2 × {10^{ - 11}} . solubility of this compound in gram per 1

English

Gujarati

Hindi

6-2.Equilibrium-II (Ionic Equilibrium)

medium

The solubility product of $Mg{(OH)_2}$ is $1.2 \times {10^{ - 11}}$. The solubility of this compound in gram per $100\,c{m^3}$ of solution is

A

$1.4 \times {10^{ - 4}}$

B

$8.16 \times {10^{ - 4}}$

C

$0.816$

D

$1.4$

Solution

(b) $Mg{(OH)^2} \rightleftharpoons \mathop {M{g^{2 + }}}\limits_{({\rm{s}})} + \mathop {2O{H^ – }}\limits_{{{(2{\rm{s}})}^2}} $

${K_{sp}} = 4{S^3} \Rightarrow S = \sqrt[3]{{\frac{{{K_{sp}}}}{4}}} = \sqrt[3]{{\frac{{1.2 \times {{10}^{ – 11}}}}{4}}}$

$S = 8.16 \times {10^{ – 4}}$

Standard 11

Chemistry

Share

Similar Questions

Silver ions are added to a solution with $[Br^-] = [Cl^-] = [CO_3^{-2}]$ $= [AsO_4^{-3}] = 0.1\,M$. Which compound will precipitate with lowest $[Ag^+]$ ?

medium

The solubility product of a salt having general formula $M{X_2},$ in water is : $4 \times {10^{ – 12}}$. The concentration of ${M^{2 + }}$ ions in the aqueous solution of the salt is

medium

(AIEEE-2005)

The values of $K_{sp}$ of $CaCO_3$ and $CaC_2O_4$ are $4.7 \times 10^{-9}$ and $1.3 \times 10^{-9}$ respectively at $25\,^oC.$ If the mixture of these two is washed with water, what is the concentration of $Ca^{2+}$ ions in water …………..$ \times 10^{-5}\, M$?

normal

(NEET-2013)

A saturated solution of $A{g_2}S{O_4}$ is $2.5 \times {10^{ – 2}}$ $M$; The value of its solubility product is

hard

If the concentration of lead iodide in its saturated solution at ${25\,^o}C$ be $2 \times {10^{ – 3}}$ moles per litre, then its solubility product is

medium