The solution of frac{1}{2} +cosx + cos2 | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\frac{1}{2}+\frac{1}{2 \sin \frac{x}{2}} 2 \sin \frac{x}{2}(\cos x+\cos 2 x+\cos 3 x+\cos 4 x)=0$

$=\frac{1}{2}+\frac{1}{2 \sin \frac{x}{2}}\left(

Vedclass · Accepted Answer

$x=\frac{2n\pi}{9},n\in I,n
eq 9m,m\in I$

Vedclass · Answer

$\frac{1}{2}+\frac{1}{2 \sin \frac{x}{2}} 2 \sin \frac{x}{2}(\cos x+\cos 2 x+\cos 3 x+\cos 4 x)=0$

$=\frac{1}{2}+\frac{1}{2 \sin \frac{x}{2}}\left(\sin \frac{9 x}{2}-\sin \frac{x}{2}ight)=0$

$=\frac{\sin \left(\frac{9 \mathrm{x}}{2}ight)}{\sin \left(\frac{\mathrm{x}}{2}ight)}=0 $

$ \Rightarrow \mathrm{x}=\frac{2 \mathrm{n} \pi}{9}, \mathrm{n} 
eq 9 \mathrm{mm} \in \mathrm{I}$

The solution of $\frac{1}{2} +cosx + cos2x + cos3x + cos4x = 0$ is

Similar Questions

If $\sqrt{3}\left(\cos ^{2} x\right)=(\sqrt{3}-1) \cos x+1,$ the number of solutions of the given equation when $x \in\left[0, \frac{\pi}{2}\right]$ is

The number of values of $x$ for which $sin2x + sin4x = 2$ is

If $tanA + cotA = 4$, then $tan^4A + cot^4A$ is equal to

Let $A=\left\{\theta \in R:\left(\frac{1}{3} \sin \theta+\frac{2}{3} \cos \theta\right)^2=\frac{1}{3} \sin ^2 \theta+\frac{2}{3} \cos ^2 \theta\right\}$.Then

If $\cos {40^o} = x$ and $\cos \theta = 1 - 2{x^2}$, then the possible values of $\theta $ lying between ${0^o}$ and ${360^o}$is