The solution set of the equation pq{x^2} - {( | vedclass

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Question

(d) Given equation $(pq)\,{x^2} - {(p + q)^2}x + {(p + q)^2} = 0$

Let solution set is $\left\{ {\frac{{p + q}}{p},\,\frac{{p + q}}{q}} \right\}$

Vedclass · Accepted Answer

$\left\{ {\frac{{p + q}}{p},\,\frac{{p + q}}{q}} \right\}$

Vedclass · Answer

(d) Given equation $(pq)\,{x^2} - {(p + q)^2}x + {(p + q)^2} = 0$

Let solution set is $\left\{ {\frac{{p + q}}{p},\,\frac{{p + q}}{q}} ight\}$

Sum of roots = $\frac{{{{(p + q)}^2}}}{{pq}}$

==> $\frac{{p + q}}{p} + \frac{{p + q}}{q} = \frac{{{{(p + q)}^2}}}{{pq}}$

Similarly, product of roots = $\frac{{{{(p + q)}^2}}}{{pq}}$

==> $\frac{{p + q}}{p} 	imes \frac{{p + q}}{q} = \frac{{{{(p + q)}^2}}}{{pq}}$.

The solution set of the equation $pq{x^2} - {(p + q)^2}x + {(p + q)^2} = 0$ is

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