The specific heat of alcohol is about half that of water. Suppose you have identical masses of alcohol and water. The alcohol is initially at temperature $T_A$ . The water is initially at a different temperature $T_W$ . Now the two fluids are mixed in the same container and allowed to come into thermal equilibrium, with no loss of heat to the surroundings. The final temperature of the mixture will be
The specific heat of alcohol is about half that of water. Suppose you have identical masses of alcohol and water. The alcohol is initially at temperature $T_A$ . The water is initially at a different temperature $T_W$ . Now the two fluids are mixed in the same container and allowed to come into thermal equilibrium, with no loss of heat to the surroundings. The final temperature of the mixture will be
- A
closer to $T_A$ than $T_W$
- B
closer to $T_W$ than $T_A$
- C
exactly halfway between $T_A$ and $T_W$
- D
dependent on the volume of alcohol used.
Similar Questions
$2\ kg$ ice at $-20^o\ C$ is mixed with $5\ kg$ water at $20^o\ C$. Then final amount of water in the mixture would be ; Given specific heat of ice $= 0.5\ cal/g^o\ C$, specific heat of water $= 1\ cal/g^o\ C$, Latent heat of fusion of ice $= 80\ cal/g$ ........ $kg$
$2\ kg$ ice at $-20^o\ C$ is mixed with $5\ kg$ water at $20^o\ C$. Then final amount of water in the mixture would be ; Given specific heat of ice $= 0.5\ cal/g^o\ C$, specific heat of water $= 1\ cal/g^o\ C$, Latent heat of fusion of ice $= 80\ cal/g$ ........ $kg$
Ice at $0^o C$ is added to $200 \,\,g$ of water initially at $70^o C$ in a vacuum flask. When $50\,\, g$ of ice has been added and has all melted the temperature of the flask and contents is $40^o C$. When a further $80\,\,g$ of ice has been added and has all metled, the temperature of the whole is $10^o C$. Calculate the specific latent heat of fusion of ice.[Take $S_w =1\,\, cal /gm ^o C$.]
Ice at $0^o C$ is added to $200 \,\,g$ of water initially at $70^o C$ in a vacuum flask. When $50\,\, g$ of ice has been added and has all melted the temperature of the flask and contents is $40^o C$. When a further $80\,\,g$ of ice has been added and has all metled, the temperature of the whole is $10^o C$. Calculate the specific latent heat of fusion of ice.[Take $S_w =1\,\, cal /gm ^o C$.]
Find the quantity of heat required to convert $40\; gm$ of ice at $-20^{\circ} C$ into water at $20^{\circ} C$. Given $L _{\text {ice }}$ $=0.336 \times 10^6 J / kg$.
specific heat of ice $=2100 \;J / kg - K$ sp heat of water= $4200\; J / kg - K$
Find the quantity of heat required to convert $40\; gm$ of ice at $-20^{\circ} C$ into water at $20^{\circ} C$. Given $L _{\text {ice }}$ $=0.336 \times 10^6 J / kg$.
specific heat of ice $=2100 \;J / kg - K$ sp heat of water= $4200\; J / kg - K$
A vessel contains $110\,\,g$ of water. The heat capacity of the vessel is equal to $10\,\,g$ of water. The initial temperature of water in vessel is $10\,^oC.$ If $220\,\,g$ of hot water at $70\,^oC$ is poured in the vessel, the final temperature neglecting radiation loss, will be nearly equal to ........ $^oC$
A vessel contains $110\,\,g$ of water. The heat capacity of the vessel is equal to $10\,\,g$ of water. The initial temperature of water in vessel is $10\,^oC.$ If $220\,\,g$ of hot water at $70\,^oC$ is poured in the vessel, the final temperature neglecting radiation loss, will be nearly equal to ........ $^oC$
One end of a $2.35\,\,m$ long and $2.0\,\,cm$ radius aluminium rod$(K = 235 \,\,W.m^{-1}K^{-1})$ is held at $20^0\,\,C$. The other end of the rod is in contact with a block of ice at its melting point. The rate in $kg.s^{-1}$ at which ice melts is
[Take latent heat of fusion for ice as $\frac{{10}}{3} ×10^5 J.kg^{-1} $]
One end of a $2.35\,\,m$ long and $2.0\,\,cm$ radius aluminium rod$(K = 235 \,\,W.m^{-1}K^{-1})$ is held at $20^0\,\,C$. The other end of the rod is in contact with a block of ice at its melting point. The rate in $kg.s^{-1}$ at which ice melts is
[Take latent heat of fusion for ice as $\frac{{10}}{3} ×10^5 J.kg^{-1} $]