The speed of a projectile at its maximum height is $\frac {\sqrt 3}{2}$ times its initial speed. If the range of the projectile is $P$ times the maximum height attained by it, $P$ is equal to
$\frac {4}{3}$
$2 \sqrt 3$
$4 \sqrt 3$
$\frac {3}{4}$
A particle is projected from ground with velocity $u$ at angle $\theta$ from horizontal. Match the following two columns.
Column $I$ | Column $II$ |
$(A)$ Average velocity between initial and final points | $(p)$ $u \sin \theta$ |
$(B)$ Change in velocity between initial and final points | $(q)$ $u \cos \theta$ |
$(C)$ Change in velocity between initial and final points | $(r)$ Zero |
$(D)$ Average velocity between initial and highest points | $(s)$ None of the above |
Two particles $A$ and $B$ are moving in horizontal plane as shown in figure at $t = 0$ , then time after which $A$ will catch $B$ will be.......$s$
At $t = 0$ a projectile is fired from a point $O$(taken as origin) on the ground with a speed of $50\,\, m/s$ at an angle of $53^o$ with the horizontal. It just passes two points $A \& B$ each at height $75 \,\,m$ above horizontal as shown The distance (in metres) of the particle from origin at $t = 2$ sec.
Two balls are projected from the same point simultaneously.First ball is projected vertically upwards and the second ball at an angle of projection $60^o$ to the ground level. Both the balls reach the ground simultaneously. The ratio of their velocities are
The time of flight of an object projected with speed $20 \,ms ^{-1}$ at an angle $30^{\circ}$ with the horizontal, is .... $s$