A stone is projected with a velocity 20 √{2},m / s at an angle of 45^{circ} to horizontal. average

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3-2.Motion in Plane

hard

A stone is projected with a velocity $20 \sqrt{2}\,m / s$ at an angle of $45^{\circ}$ to the horizontal. The average velocity of stone during its motion from starting point to its maximum height is $..........\,m/s$ (take $g=10\,m / s ^2$ )

A

$20$

B

$20 \sqrt{5}$

C

$5 \sqrt{5}$

D

$10 \sqrt{5}$

Solution

(d)

$T=(24 \sin \theta / g)=4\,s , R=u^2 \sin ^2 \theta / g=80\,m$

and $H=\frac{u^2 \sin ^2 \theta}{2 g}=20\,m$

Now, average velocity $=\frac{\text { Displacement }}{\text { Time }}$

$=\frac{\sqrt{(20)^2+(40)^2}}{2}$

$=10 \sqrt{5}\,m / s$

Standard 11

Physics

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