Gujarati
8. Sequences and Series
easy

The sum of infinity of a geometric progression is $\frac{4}{3}$ and the first term is $\frac{3}{4}$. The common ratio is

A

$7/16$

B

$9/16$

C

$1/9$

D

$7/9$

Solution

(a) According to condition $\frac{{3/4}}{{1 – r}} = \frac{4}{3}$

$ \Rightarrow $$r = \frac{7}{{16}}$.

Standard 11
Mathematics

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