4-2.Quadratic Equations and Inequations
normal

The sum of integral values of $a$ such that the equation $||x\ -2|\ -|3\ -x||\ =\ 2\ -a$ has a solution

A

$1$

B

$2$

C

$3$

D

$4$

Solution

$0 \leq \mathrm{LHS}<1$

$\{$ as it is absolute difference of distance of point $\mathrm{P}(\mathrm{x}, 0) \text { from } \mathrm{A}(2,0)  \,\,and\,\,  \mathrm{B}(3,0)\} 0 \leq 2-\mathrm{a} \leq 1$

$\Rightarrow 1 \leq a \leq 2 \quad$ sum $=3$

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.