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4-2.Quadratic Equations and Inequations
normal
The sum of integral values of $a$ such that the equation $||x\ -2|\ -|3\ -x||\ =\ 2\ -a$ has a solution
A
$1$
B
$2$
C
$3$
D
$4$
Solution
$0 \leq \mathrm{LHS}<1$
$\{$ as it is absolute difference of distance of point $\mathrm{P}(\mathrm{x}, 0) \text { from } \mathrm{A}(2,0) \,\,and\,\, \mathrm{B}(3,0)\} 0 \leq 2-\mathrm{a} \leq 1$
$\Rightarrow 1 \leq a \leq 2 \quad$ sum $=3$
Standard 11
Mathematics