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7.Binomial Theorem
medium
The sum of the last eight coefficients in the expansion of ${(1 + x)^{15}}$ is
A
${2^{16}}$
B
${2^{15}}$
C
${2^{14}}$
D
None of these
Solution
(c) We have $^{15}{C_0} + {\,^{15}}{C_1} + … + {\,^{15}}{C_{15}} = {2^{15}}$
$ \Rightarrow \,\,\,2{(^{15}}{C_8} + {\,^{15}}{C_9} + … + {\,^{15}}{C_{15}}) = {2^{15}}$ $(\because \,{\,^n}{C_r} = {\,^n}{C_{n – r}})$
==> $^{15}{C_8} + {\,^{15}}{C_9} + … + {\,^{15}}{C_{15}} = {2^{14}}$
Standard 11
Mathematics