Gujarati
Hindi
1.Units, Dimensions and Measurement
normal

The temperature of two bodies measured by a thermometer are $t_1 = 20\, ^oC + 0.5\, ^oC$ and $t_2 = 50\,^oC + 0.5\, ^oC$. The temperature difference and the error there in is

A$30{\,^o}C \pm 1{\,^o}C\,$
B$70{\,^o}C \pm 0.5{\,^o}C\,$
C$30{\,^o}C \pm 0.5{\,^o}C\,$
D$70{\,^o}C \pm 1{\,^o}C\,$

Solution

Here,
$\mathrm{t}_{1}=20^{\circ} \mathrm{C} \pm 0.5^{\circ} \mathrm{C}$
$\mathrm{t}_{2}=50^{\circ} \mathrm{C} \pm 0.5^{\circ} \mathrm{C}$
The temperature difference of two bodies is
$\mathrm{t}=\mathrm{t}_{2}-\mathrm{t}_{1}=50^{\circ} \mathrm{C}-20^{\circ}=30^{\circ} \mathrm{C}$
The error in temperature differerence is given by
$\Delta \mathrm{t}=\left(\Delta \mathrm{t}_{1}+\Delta \mathrm{t}_{2}\right)$
$=\left(0.5^{\circ} \mathrm{C}+0.5^{\circ} \mathrm{C}\right)=1^{\circ} \mathrm{C}$
The temperature difference is $30^{\circ} \mathrm{C} \pm 1^{\circ} \mathrm{C}$
Standard 11
Physics

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