14.Waves and Sound
medium

The tension of a stretched string is increased by $69\%$. In order to keep its frequency of vibration constant, its length must be increased by .... $\%$

A

$20$

B

$30$

C

$\sqrt {69}$

D

$69$

Solution

(b)$n \propto \frac{{\sqrt T }}{l}$$ \Rightarrow l \propto \sqrt T $(As $n$= constant)
==>$\frac{{{l_2}}}{{{l_1}}} = \sqrt {\frac{{{T_2}}}{{{T_1}}}} = {l_1}\sqrt {\frac{{169}}{{100}}} \Rightarrow {l_2} = 1.3{l_1} = {l_1} + 30\% $ of ${l_1}$

Standard 11
Physics

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