7.Gravitation
medium

The time period of a satellite in a circular orbit of radius $R$ is $T$. The period of another satellite in a circular orbit of radius $9 R$ is............ $T$

A

$9$

B

$27$

C

$12$

D

$3$

(JEE MAIN-2021)

Solution

$T ^{2} \propto R ^{3}$

$\left(\frac{ T ^{\prime}}{ T }\right)^{2}=\left(\frac{9 R }{ R }\right)^{3}$

$T ^{2}= T ^{2} \times 9^{3}$

$T ^{\prime}= T \times 3^{3}$

$T ^{\prime}=27 T$

Standard 11
Physics

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