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7.Gravitation
medium
The time period of a satellite of earth is $5\, hours$. If the separation between the centre of earth and the satellite is increased to $4\, times$ the previous value, the new time period will become ....... $h$
A
$10$
B
$80$
C
$40$
D
$20$
Solution
$\mathrm{T} \propto \mathrm{r}^{\frac{3}{2}}$
$\frac{\mathrm{T}^{1}}{\mathrm{T}}=(4)^{\frac{3}{2}}$
$\mathrm{T}^{1}=5 \times 8=40$
Standard 11
Physics