Gujarati
Hindi
7.Gravitation
medium

The time period of a satellite of earth is $5\, hours$. If the separation between the centre of earth and the satellite is increased to $4\, times$ the previous value, the new time period will become ....... $h$

A

$10$

B

$80$

C

$40$

D

$20$

Solution

$\mathrm{T} \propto \mathrm{r}^{\frac{3}{2}}$

$\frac{\mathrm{T}^{1}}{\mathrm{T}}=(4)^{\frac{3}{2}}$

$\mathrm{T}^{1}=5 \times 8=40$

Standard 11
Physics

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