The torque of the force overrightarrow F = (2 | vedclass

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Question

(b) $\overrightarrow 	au = \overrightarrow {r\,} 	imes \overrightarrow F $ $ = \left| {\begin{array}{*{20}{c}}{\hat i\,\,}&{\hat j\,\,}&{\ha

Vedclass · Accepted Answer

$17\hat i - 6\hat j - 13\hat k$

Vedclass · Answer

(b) $\overrightarrow 	au = \overrightarrow {r\,} 	imes \overrightarrow F $ $ = \left| {\begin{array}{*{20}{c}}{\hat i\,\,}&{\hat j\,\,}&{\hat k}\{\,3\,\,\,}&{\,\,2\,\,\,\,\,}&3\{\,2\,\,\,}&{ - 3\,\,\,\,\,\,}&{\,\,4\,\,}\end{array}} ight|\,$

$ = \left[ {(2 	imes 4) - (3 	imes - 3)} ight]\,\,\hat i + \left[ {(2 	imes 3) - (3 	imes 4)} ight]\,\hat j + \left[ {(3 	imes - 3) - (2 	imes 2)} ight]\,\hat k$

$ = 17\,\hat i - 6\,\hat j - 13\,\hat k$

The torque of the force $\overrightarrow F = (2\hat i - 3\hat j + 4\hat k\,)N$ acting at the point $\overrightarrow {r\,} = (3\hat i + 2\hat j + 3\hat k)\,m$ about the origin be

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