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8. Sequences and Series
easy
The two geometric means between the number $1$ and $64$ are
A
$1$ and $64$
B
$4$ and $16$
C
$2$ and $16$
D
$8$ and $16$
Solution
(b) Let $1,a, b, 64$
$ \Rightarrow {a^2} = b$ and ${b^2} = 64a$
$ \Rightarrow a = 4$ and $b = 16$.
Standard 11
Mathematics