The unit of intensity of electric field is
$Newton/Coulomb$
$Joule/Coulomb$
$Volt - metre$
$Newton/metre$
(a) $E = \frac{F}{{{q_0}}} → Newton/Coulomb$
An electron experiences a force equal to its weight when placed in an electric field. The intensity of the field will be
The electric field intensity at a point in vacuum is equal to
A positively charged thin metal ring of radius $R$ is fixed in the $xy – $ plane with its centre at the $O$. A negatively charged particle $P$ is released from rest at the point $(0,\,0,\,{z_0})$, where ${z_0} > 0$. Then the motion of $P$ is
Mention characteristics of electric field.
Two point charges $q_{1}$ and $q_{2},$ of magnitude $+10^{-8} \;C$ and $-10^{-8}\; C ,$ respectively, are placed $0.1 \;m$ apart. Calculate the electric fields at points $A, B$ and $C$ shown in Figure
Confusing about what to choose? Our team will schedule a demo shortly.