The value of {4^{1/3}}{.4^{1/9}}{.4^{1/27}}.. | vedclass

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Question

(a) ${4^{1/3}}{.4^{1/9}}{.4^{1/27}}......\infty $

$	herefore $ $S = {4^{1/3 + 1/9 + 1/27}}......\infty $

$ \Rightarrow $ $S = {4^{\left( {\frac

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(a) ${4^{1/3}}{.4^{1/9}}{.4^{1/27}}......\infty $

$	herefore $ $S = {4^{1/3 + 1/9 + 1/27}}......\infty $

$ \Rightarrow $ $S = {4^{\left( {\frac{{1/3}}{{1 - 1/3}}} ight)}} = {4^{\frac{{1/3}}{{2/3}}}}$$ $

$\Rightarrow $ $S = {4^{1/2}}$

$ \Rightarrow $ $S = 2$.

The value of ${4^{1/3}}{.4^{1/9}}{.4^{1/27}}...........\infty $ is

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