Gujarati
Hindi
7.Gravitation
normal

The value of escape velocity on a certain planet is $2\, km/s$ . Then the value of orbital speed for a satellite orbiting close to its surface is

A

$12\,km/s$

B

$1\, km/s$

C

$\sqrt 2\,km/s$

D

$2\sqrt 2\, km / s$

Solution

${v_0} = \frac{{{v_e}}}{{\sqrt 2 }} = \frac{2}{{\sqrt 2 }} = \sqrt 2 \,km/s$

Standard 11
Physics

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