The value of m for which y = mx + 6 is a tang | vedclass

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Question

(a) If $y = mx + c$ touches $\frac{{{x^2}}}{{{a^2}}} - \frac{{{y^2}}}{{{b^2}}} = 1,$

then ${c^2} = {a^2}{m^2} - {b^2}$.

Here $c = 6,\,\,{a^2} =

Vedclass · Accepted Answer

$\sqrt {\frac{{17}}{{20}}} $

Vedclass · Answer

(a) If $y = mx + c$ touches $\frac{{{x^2}}}{{{a^2}}} - \frac{{{y^2}}}{{{b^2}}} = 1,$

then ${c^2} = {a^2}{m^2} - {b^2}$.

Here $c = 6,\,\,{a^2} = 100,\,\,{b^2} = 49$

$	herefore 36 = 100{m^2} - 49$

$\Rightarrow 100{m^2} = 85 $

$\Rightarrow m = \sqrt {\frac{{17}}{{20}}} $.

The value of m for which $y = mx + 6$ is a tangent to the hyperbola $\frac{{{x^2}}}{{100}} - \frac{{{y^2}}}{{49}} = 1$, is

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