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3 and 4 .Determinants and Matrices
normal
$\left| {\,\begin{array}{*{20}{c}}2&8&4\\{ - 5}&6&{ - 10}\\1&7&2\end{array}\,} \right|$ = . . ..
A
$-440$
B
$0$
C
$328$
D
$488$
Solution
(b) $\left| {\,\begin{array}{*{20}{c}}2&8&4\\{ – 5}&6&{ – 10}\\1&7&2\end{array}\,} \right|\, = 2\,\left| {\,\begin{array}{*{20}{c}}2&8&2\\{ – 5}&6&{ – 5}\\1&7&1\end{array}\,} \right| = 0$
(Taking $2$ common from ${C_3}$).
Standard 12
Mathematics