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3 and 4 .Determinants and Matrices
medium
$\left| {\,\begin{array}{*{20}{c}}1&1&1\\1&{1 - x}&1\\1&1&{1 + y}\end{array}\,} \right|$ = . . .
A
$3 - x + y$
B
$(1 - x)(1 + y)$
C
$xy$
D
$ - xy$
Solution
(d) $\left| {\,\begin{array}{*{20}{c}}1&1&1\\1&{1 – x}&1\\1&1&{1 + y}\end{array}\,} \right| = \left| {\,\begin{array}{*{20}{c}}1&0&0\\1&{ – x}&x\\1&0&y\end{array}\,} \right| = – xy$.
Standard 12
Mathematics
