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7.Gravitation
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The variation of acceleration due to gravity $g$ with distance $d$ from centre of the earth is best represented by ($R =$ Earth's radius)
A
B
C
D
Solution
with depth
$g_{1}=g\left(1-\frac{(d)}{R}\right)$
As depth $d$ goes on increasing $g_{1}$ goes on decreasing, it remains maximum at the surface of Earth. The above equation is in the form of straight line.
With height
$g_{2}=g\left(1-\frac{2 h}{R}\right)$
$=g-\frac{2 g h}{R}$
$g_{2} \propto \frac{1}{R}(\text { Hyperbola })$
Acceleration due to gravity goes on decreasing as the $h$ above Earth surface increases.
Hence the correct answer is option $B$.
Standard 11
Physics
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