The variation of electrostatic potential with | vedclass

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Question

for $r$

$V =\frac{ q }{4 \pi \varepsilon_{0} R }=$ constant

for $r \geq R$

$V =\frac{ q }{4 \pi \varepsilon_{0} r }= V \propto \frac{1}{ r }$

Vedclass · Accepted Answer

Vedclass · Answer

for $r$

$V =\frac{ q }{4 \pi \varepsilon_{0} R }=$ constant

for $r \geq R$

$V =\frac{ q }{4 \pi \varepsilon_{0} r }= V \propto \frac{1}{ r }$

The variation of electrostatic potential with radial distance $r$ from the centre of a positively charged metallic thin shell of radius $R$ is given by the graph

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