2. Electric Potential and Capacitance
medium

The variation of electrostatic potential with radial distance $r$ from the centre of a positively charged metallic thin shell of radius $R$ is given by the graph

A
B
C
D
(NEET-2020) (AIIMS-2013)

Solution

for $r$

$V =\frac{ q }{4 \pi \varepsilon_{0} R }=$ constant

for $r \geq R$

$V =\frac{ q }{4 \pi \varepsilon_{0} r }= V \propto \frac{1}{ r }$

Standard 12
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.