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2.Motion in Straight Line
easy
The velocity of a bullet is reduced from $200\,m/s$ to $100\,m/s $ while travelling through a wooden block of thickness $10\,cm$. Assuming it to be uniform, the retardation will be
A$10 \times {10^4}$ $m/s^2$
B$12 \times {10^4}$ $m/s^2$
C$13.5 \times {10^4}$ $m/s^2$
D$15 \times {10^4}$ $m/s^2$
(AIIMS-2001)
Solution
(d) $u = 200\;m/s,\;v = 100\;m/s,\;s = 0.1\;m$
$a = \frac{{{u^2} – {v^2}}}{{2s}} = \frac{{{{(200)}^2} – {{(100)}^2}}}{{2 \times 0.1}} = 15 \times {10^4}\,m/{s^2}$
$a = \frac{{{u^2} – {v^2}}}{{2s}} = \frac{{{{(200)}^2} – {{(100)}^2}}}{{2 \times 0.1}} = 15 \times {10^4}\,m/{s^2}$
Standard 11
Physics
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