Velocity of projectile at intial point A is left( {2hat{i} + 3hat{j}} right) m/s . It's ve

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3-2.Motion in Plane

easy

The velocity of projectile at the intial point $A$ is $\left( {2\hat i + 3\hat j} \right)$ $m/s $ . It's velocity (in $m/s$) at point $B$ is

$\;\left( { - 2\hat i - 3\hat j} \right)$

$\;\left( { - 2\hat i + 3\hat j} \right)$

$\;\left( {2\hat i - 3\hat j} \right)$

$\;\left( {2\hat i + 3\hat j} \right)$

(AIPMT-2013)

Solution

$\begin{array}{l}
At\,{\rm{ point}}\,B\,X\,component\,of\,velocity\,\\
remains\,unchange\,while\,Y\,component\\
reverses\,its\,direction\\
\therefore \,The\,velocity\,of\,the\,projectile\,at\,{\rm{ point}}\\
B\,is\,2\hat i – 3\hat j\,m/s.
\end{array}$

Standard 11

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(JEE MAIN-2024)

The velocity of projectile at the intial point $A$ is $\left( {2\hat i + 3\hat j} \right)$ $m/s $ . It's velocity (in $m/s$) at point $B$ is

Solution

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