The velocity of projectile at the intial point $A$ is $\left( {2\hat i + 3\hat j} \right)$ $m/s $ . It's velocity (in $m/s$) at point $B$ is
$\;\left( { - 2\hat i - 3\hat j} \right)$
$\;\left( { - 2\hat i + 3\hat j} \right)$
$\;\left( {2\hat i - 3\hat j} \right)$
$\;\left( {2\hat i + 3\hat j} \right)$
The maximum height attained by a projectile is increased by $10\,\%$ by increasing its speed of projection, without changing the angle of projection. The percentage increases in the horizontal range will be $...........\,\%$
Two projectiles $A$ and $B$ are thrown with the same speed such that $A$ makes angle $\theta$ with the horizontal and $B$ makes angle $\theta$ with the vertical, then
A ball of mass $m$ is thrown vertically upwards. Another ball of mass $2m$ is thrown at an angle $\theta $ with the vertical. Both of them stay in air for same period of time. The heights attained by the two balls are in the ratio of
For a projectile, the ratio of maximum height reached to the square of flight time is ($g = 10 ms^{-2}$)
The maximum horizontal range of a projectile is $400\;m$.The maximum height atteined by it?