The velocity of water waves $v$ may depend upon their wavelength $\lambda $, the density of water $\rho $ and the acceleration due to gravity $g$. The method of dimensions gives the relation between these quantities as
${v^2} \propto \lambda {g^{ - 1}}{\rho ^{ - 1}}$
${v^2} \propto g\lambda \rho $
${v^2} \propto g\lambda $
${v^2} \propto {g^{ - 1}}{\lambda ^{ - 3}}$
Consider two physical quantities A and B related to each other as $E=\frac{B-x^2}{A t}$ where $E, x$ and $t$ have dimensions of energy, length and time respectively. The dimension of $A B$ is
The dimensions of couple are
A force is represented by $\mathrm{F}=a \mathrm{x}^2+\mathrm{bt}^{1 / 2}$. Where $\mathrm{x}=$ distance and $\mathrm{t}=$ time. The dimensions of $\mathrm{b}^2 / \mathrm{a}$ are :
A spherical body of mass $m$ and radius $r$ is allowed to fall in a medium of viscosity $\eta $. The time in which the velocity of the body increases from zero to $0.63$ times the terminal velocity $(v)$ is called time constant $(\tau )$. Dimensionally $\tau $ can be represented by
The time dependence of a physical quantity $P$ is given by $P\, = \,{P_0}\,{e^{ - \alpha {t^2}}}$ where $\alpha $ is a constant and $t$ is the time then constant $\alpha $ is