The vertices of a triangle are $\mathrm{A}(-1,3), \mathrm{B}(-2,2)$ and $\mathrm{C}(3,-1)$. $A$ new triangle is formed by shifting the sides of the triangle by one unit inwards. Then the equation of the side of the new triangle nearest to origin is :
The vertices of a triangle are $\mathrm{A}(-1,3), \mathrm{B}(-2,2)$ and $\mathrm{C}(3,-1)$. $A$ new triangle is formed by shifting the sides of the triangle by one unit inwards. Then the equation of the side of the new triangle nearest to origin is :
- [JEE MAIN 2024]
- A
$x-y-(2+\sqrt{2})=0$
- B
$-\mathrm{x}+\mathrm{y}-(2-\sqrt{2})=0$
- C
$x+y-(2-\sqrt{2})=0$
- D
$x+y+(2-\sqrt{2})=0$
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- [IIT 1981]