Gujarati
11.Thermodynamics
normal

An ideal monoatomic gas is taken round the cycle $ABCDA$ shown in the $PV$ diagram in the given fig. The work done during the cycle is

A

$\frac{1}{2}PV$

B

$2\;PV$

C

$PV$

D

$Zero$

Solution

(c) Work done $=$ area under $P-V$ graph.

$=\mathrm{AB} \times \mathrm{BC}$

$=(2 P-P) \times(2 V-V)$

$=P V$

Standard 11
Physics

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