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11.Thermodynamics
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An ideal monoatomic gas is taken round the cycle $ABCDA$ shown in the $PV$ diagram in the given fig. The work done during the cycle is

A
$\frac{1}{2}PV$
B
$2\;PV$
C
$PV$
D
$Zero$
Solution
(c) Work done $=$ area under $P-V$ graph.
$=\mathrm{AB} \times \mathrm{BC}$
$=(2 P-P) \times(2 V-V)$
$=P V$
Standard 11
Physics
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