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11.Thermodynamics
hard
The volume of an ideal gas $(\gamma=1.5)$ is changed adiabatically from $5$ litres to $4$ litres. The ratio of initial pressure to final pressure is:
A
$\frac{4}{5}$
B
$\frac{16}{25}$
C
$\frac{8}{5 \sqrt{5}}$
D
$\frac{2}{\sqrt{5}}$
(JEE MAIN-2024)
Solution
For Adiabatic process
$P_i V_i=P_f V_f^\gamma$
$P_i(5)^{1.5}=P_f(4)^{1.5}$
$\frac{P_i}{P_f}=\left(\frac{4}{5}\right)^{\frac{3}{2}}=\frac{4}{5} \cdot\left(\frac{4}{5}\right)^{\frac{1}{2}} \Rightarrow \frac{8}{5 \sqrt{5}}$
Standard 11
Physics
Similar Questions
easy
Match List$-I$ with List$-II$
List$-I$ | List$-II$ |
$(a)$ Isothermal | $(i)$ Pressure constant |
$(b)$ Isochoric | $(ii)$ Temperature constant |
$(c)$ Adiabatic | $(iii)$ Volume constant |
$(d)$ Isobaric | $(iv)$ Heat content is constant |
Choose the correct answer from the options given below