The work done by a force vec F = (-6x^3h | vedclass

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Question

$\mathrm{W}=\int_{\mathrm{A}}^{\mathrm{B}} \mathrm{F}_{\mathrm{x}} \mathrm{dx} \Rightarrow \mathrm{W}=\int_{\mathrm{x}-4}^{\mathrm{x}-2}\left(-6 \math

Vedclass · Accepted Answer

$360$

Vedclass · Answer

$\mathrm{W}=\int_{\mathrm{A}}^{\mathrm{B}} \mathrm{F}_{\mathrm{x}} \mathrm{dx} \Rightarrow \mathrm{W}=\int_{\mathrm{x}-4}^{\mathrm{x}-2}\left(-6 \mathrm{x}^{3}\right) \mathrm{d} \mathrm{x}$

$=-6\left[\frac{\mathrm{x}^{4}}{4}\right]_{x-4}^{x-2}=\left(\frac{-3}{2}\right)(-240)=360 \mathrm{J}$

The work done by a force $\vec F = (-6x^3\hat i)\, N$, in displacing a particle from $x = 4\, m$ to $x = -2\, m$ is .............. $\mathrm{J}$

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