9-1.Fluid Mechanics
normal

The work done in blowing a soap bubble of radius $0.2\,m$, given that the surface tension of soap solution is $60\times10^{-3}\, N/M$ is

A

$24\pi \times10^{-4}\,J$

B

$24\pi \times10^{-4}\,J$

C

$96\pi \times10^{-4}\,J$

D

$192\pi \times10^{-4}\,J$

Solution

$\mathrm{W}=\mathrm{T} \Delta \mathrm{A}=\mathrm{T} \times 2\left[4 \pi \mathrm{R}^{2}\right]$

$=60 \times 10^{-3} \times 8 \pi \times(0.2)^{2}$

$=1.92 \pi \times 10^{-4} \mathrm{\,J}$

Standard 11
Physics

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