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9-1.Fluid Mechanics
normal
The work done in blowing a soap bubble of radius $0.2\,m$, given that the surface tension of soap solution is $60\times10^{-3}\, N/M$ is
A
$24\pi \times10^{-4}\,J$
B
$24\pi \times10^{-4}\,J$
C
$96\pi \times10^{-4}\,J$
D
$192\pi \times10^{-4}\,J$
Solution
$\mathrm{W}=\mathrm{T} \Delta \mathrm{A}=\mathrm{T} \times 2\left[4 \pi \mathrm{R}^{2}\right]$
$=60 \times 10^{-3} \times 8 \pi \times(0.2)^{2}$
$=1.92 \pi \times 10^{-4} \mathrm{\,J}$
Standard 11
Physics