The work done in increasing the length of a metre long wire of cross-sectional area ........ $J.$ $1\,mm^2$ through $1\,mm$ will be $(Y = 2 \times 10^{11}\,Nm^{-2})$

  • A

    $0.1$

  • B

    $5$

  • C

    $10$

  • D

    $250$

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