The work done in splitting a drop of water of $1\, mm$ radius into $10^6$ droplets is (surface tension of water $72\times10^{-3}\, N/m$) :
The work done in splitting a drop of water of $1\, mm$ radius into $10^6$ droplets is (surface tension of water $72\times10^{-3}\, N/m$) :
- A
$5.98\times10^{-5}\, J$
- B
$10.98\times10^{-5}\, J$
- C
$16.95\times10^{-5}\, J$
- D
$8.95\times10^{-5}\, J$
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