Water is flowing continuously from a tap havi | vedclass

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Question

$\mathrm{V}_{2}^{2}=\mathrm{V}_{1}^{2}+2 \mathrm{gh}$

$\mathrm{V}_{2}^{2}=(0.04)^{2}+2 	imes 10 	imes 8 	imes 10^{-1}$

${{m{V}}_2} \simeq 4

Vedclass · Accepted Answer

$0.8 	imes {10^{ - 3}}\,m$

Vedclass · Answer

$\mathrm{V}_{2}^{2}=\mathrm{V}_{1}^{2}+2 \mathrm{gh}$

$\mathrm{V}_{2}^{2}=(0.04)^{2}+2 	imes 10 	imes 8 	imes 10^{-1}$

${{m{V}}_2} \simeq 4{\mkern 1mu} {m{m}}/{m{s}}\quad {m{D}}_1^2{{m{V}}_1} = {m{D}}_2^2{{m{V}}_2}$

$\left(8 	imes 10^{-3}ight)^{2} 	imes 0.04=\mathrm{D}_{2}^{2} 	imes 4 $

$\Rightarrow \mathrm{D}_{2}=0.8 	imes 10^{-3} \mathrm{\,m}$

Water is flowing continuously from a tap having an internal diameter $8 \times 10^{-3}\, m$. The water velocity as it leaves the tap is $0.04\, ms^{-1}$. The diameter of the water stream at a distance $8 \times 10^{-1}\, m$ below the tap is close to

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