There are m books in black cover and n books in blue cover, and all books are different. number of w

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6.Permutation and Combination

hard

There are $m$ books in black cover and $n$ books in blue cover, and all books are different. The number of ways these $(m+n)$ books can be arranged on a shelf so that all the books in black cover are put side by side is

A

$m ! n !$

B

$m !(n+1) !$

C

$(n+1) !$

D

$(m+n) !$

(KVPY-2020)

Solution

(b)

Here, $m$ books will be considered one thing. So, total $(n+1)$ things to arrange.

Standard 11

Mathematics

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(JEE MAIN-2021)