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2. Electric Potential and Capacitance
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There are two identical capacitors, the first one is uncharged and filled with a dielectric of constant $K$ while the other one is charged to potential $V$ having air between its plates. If two capacitors are joined end to end, the common potential will be
A
$\frac{V}{K-1}$
B
$\frac{K V}{K+1}$
C
$\frac{K V}{K-1}$
D
$\frac{V}{K+1}$
Solution

(d)
$V^{\prime}=\frac{K C(0)+C V}{K C+C}$
$V^{\prime}=\frac{C V}{C(1+K)}$
$V^{\prime}=\frac{V}{1+K}$
Standard 12
Physics
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