A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is a

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2. Electric Potential and Capacitance

medium

A dielectric slab of thickness $d$ is inserted in a parallel plate capacitor whose negative plate is at $x = 0$ and positive plate is at $x = 3d$. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from $0$ to $3d$

The magnitude of the electric field remains the same

The direction of the electric field remains the same

The electric potential increases continuously

Both $(b)$ and $(c)$

(IIT-1998)

Solution

(d) Even after introduction of dielectric slab, direction of electric field will be perpendicular to the plates and directed from positive plate to negative plate.
Further, magnitude of electric field in air $ = \frac{\sigma }{{{\varepsilon _0}}}$
Magnitude of electric field in dielectric $ = \frac{\sigma }{{K{\varepsilon _0}}}$
Similarly electric lines always flows from higher to lower potential, therefore, electric potential increases continuously as we move from $x = 0$ to $x = 3d$.

Standard 12

Physics

A medium having dielectric constant $K>1$ fills the space between the plates of a parallel plate capacitor. The plates have large area, and the distance between them is $d$. The capacitor is connected to a battery of voltage $V$. as shown in Figure ($a$). Now, both the plates are moved by a distance of $\frac{d}{2}$ from their original positions, as shown in Figure ($b$).

In the process of going from the configuration depicted in Figure ($a$) to that in Figure ($b$), which of the following statement($s$) is(are) correct?

normal

(IIT-2022)

Explain polarisation of polar molecule in uniform electric field.

medium

The energy and capacity of a charged parallel plate capacitor are $U$ and $C$ respectively. Now a dielectric slab of $\in _r = 6$ is inserted in it then energy and capacity becomes (Assume charge on plates remains constant)

medium

The capacity of a parallel plate condenser is $5\,\mu F$. When a glass plate is placed between the plates of the conductor, its potential becomes $1/8^{th}$ of the original value. The value of dielectric constant will be

easy

Assertion : In the absence of an external electric field, the dipole moment per unit volume of a polar dielectric is zero.

Reason : The dipoles of a polar dielectric are randomly oriented.

easy

(AIIMS-2016)

A dielectric slab of thickness $d$ is inserted in a parallel plate capacitor whose negative plate is at $x = 0$ and positive plate is at $x = 3d$. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from $0$ to $3d$

Solution

Similar Questions

Explain polarisation of polar molecule in uniform electric field.

The energy and capacity of a charged parallel plate capacitor are $U$ and $C$ respectively. Now a dielectric slab of $\in _r = 6$ is inserted in it then energy and capacity becomes (Assume charge on plates remains constant)

The capacity of a parallel plate condenser is $5\,\mu F$. When a glass plate is placed between the plates of the conductor, its potential becomes $1/8^{th}$ of the original value. The value of dielectric constant will be

Assertion : In the absence of an external electric field, the dipole moment per unit volume of a polar dielectric is zero. Reason : The dipoles of a polar dielectric are randomly oriented.

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Assertion : In the absence of an external electric field, the dipole moment per unit volume of a polar dielectric is zero.

Reason : The dipoles of a polar dielectric are randomly oriented.