There are two wire of same material and same | vedclass

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Question

Both wires are same materials so both will have same $Young's$ modulus, and let it

be. $Y.Y = \frac{{stress}}{{strain}} = \frac{F}{{A.\lef

Vedclass · Accepted Answer

$4 : 1$

Vedclass · Answer

Both wires are same materials so both will have same $Young's$ modulus, and let it

be. $Y.Y = \frac{{stress}}{{strain}} = \frac{F}{{A.\left( {\Delta L/L} \right)}},$

$F = applied\,force$

$A = \,area\,of\,cross - \,section\,of\,wire$

$Now,$

${Y_1} = {Y_2} \Rightarrow \frac{{FL}}{{\left( {{A_1}} \right)\left( {\Delta {L_1}} \right)}} = \frac{{FL}}{{\left( {{A_2}} \right)\left( {\Delta {L_2}} \right)}}$

Since load and length are same for both

$ \Rightarrow r_1^2\Delta {L_1} = r_2^2\Delta {L_2},$

$\left( {\frac{{\Delta {L_1}}}{{\Delta {L_2}}}} \right) = {\left( {\frac{{{r_2}}}{{{r_1}}}} \right)^2} = 4\,\Delta {L_1}\,:\,\Delta {L_2} = 4:1$

There are two wire of same material and same length while the diameter of second wire is two times the diameter of first wire, then the ratio of extension produced in the wires by applying same load will be

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