There were two women participating in a chess | vedclass

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Question

(c) Let there be $n$ men participants. Then the number of games that the men play between themselves is $2\;.{\;^n}{C_2}$ and the number of games that

Vedclass · Accepted Answer

$13$

Vedclass · Answer

(c) Let there be $n$ men participants. Then the number of games that the men play between themselves is $2\;.{\;^n}{C_2}$ and the number of games that the men played with the women is $2.\;(2n)$.

$	herefore $$2.{\;^n}{C_2} - 2\;.\;2n = 66$ (By hypothesis)

$ \Rightarrow $${n^2} - 5n - 66 = 0 \Rightarrow n = 11$

$	herefore $ Number of participants $ = 11\;{m{men}} + 2\;{m{women}} = 13$.

There were two women participating in a chess tournament. Every participant played two games with the other participants. The number of games that the men played between themselves proved to exceed by $66$ the number of games that the men played with the women. The number of participants is

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