2. Electric Potential and Capacitance
hard

Three charges $Q, +q$ and $+q$ are placed at the vertices of a right -angle isosceles triangle as shown below. The net electrostatic energy of the configuration is zero, if the value of $Q$ is

A

$+q$

B

$\frac{{ - \sqrt 2 q}}{{\sqrt 2  + 1}}$

C

$\frac{{ - q}}{{1 + \sqrt 2 }}$

D

$-2q$

(JEE MAIN-2019)

Solution

$\mathrm{U}_{\text {Total }}=\frac{\mathrm{kQq}}{\mathrm{a}}+\frac{\mathrm{kq}^{2}}{\mathrm{a}}+\frac{\mathrm{kQq}}{\mathrm{a} \sqrt{2}}=0$

$\Rightarrow Q=\frac{-q}{\left(1+\frac{1}{\sqrt{2}}\right)}$

Standard 12
Physics

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