- Home
- Standard 12
- Physics
2. Electric Potential and Capacitance
hard
Three charges $Q, +q$ and $+q$ are placed at the vertices of a right -angle isosceles triangle as shown below. The net electrostatic energy of the configuration is zero, if the value of $Q$ is

A
$+q$
B
$\frac{{ - \sqrt 2 q}}{{\sqrt 2 + 1}}$
C
$\frac{{ - q}}{{1 + \sqrt 2 }}$
D
$-2q$
(JEE MAIN-2019)
Solution
$\mathrm{U}_{\text {Total }}=\frac{\mathrm{kQq}}{\mathrm{a}}+\frac{\mathrm{kq}^{2}}{\mathrm{a}}+\frac{\mathrm{kQq}}{\mathrm{a} \sqrt{2}}=0$
$\Rightarrow Q=\frac{-q}{\left(1+\frac{1}{\sqrt{2}}\right)}$
Standard 12
Physics