Charges $Q _{1}$ and $Q _{2}$ arc at points $A$ and $B$ of a right angle triangle $OAB$ (see figure). The resultant electric field at point $O$ is perpendicular to the hypotenuse, then $Q _{1} / Q _{2}$ is proportional to
Charges $Q _{1}$ and $Q _{2}$ arc at points $A$ and $B$ of a right angle triangle $OAB$ (see figure). The resultant electric field at point $O$ is perpendicular to the hypotenuse, then $Q _{1} / Q _{2}$ is proportional to
- [JEE MAIN 2020]
- A
$\frac{ x _{2}^{2}}{ x _{1}^{2}}$
- B
$\frac{x_{1}^{3}}{x_{2}^{3}}$
- C
$\frac{x_{1}}{x_{2}}$
- D
$\frac{ x _{2}}{ x _{1}}$
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