Three fair coins are tossed. If both heads and tails appears, then the probability that exactly one head appears, is
Three fair coins are tossed. If both heads and tails appears, then the probability that exactly one head appears, is
- A
$\frac{3}{8}$
- B
$\frac{1}{6}$
- C
$\frac{1}{2}$
- D
$\frac{1}{3}$
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