Three identical bodies of equal mass $M$ each are moving along a circle of radius $R$ under the action of their mutual gravitational attraction. The speed of each body is
$\sqrt {\frac{{GM}}{R}} $
$\sqrt {\frac{{GM}}{3R}} $
$\sqrt {\frac{{GM}}{{\sqrt 3 R}}} $
$\sqrt {\frac{{GM}}{{\sqrt 2 R}}} $
If the distance between centres of earth and moon is $D$ and the mass of earth is $81\, times$ the mass of moon, then at what distance from centre of earth the gravitational force will be zero
A body of mass $m$ is situated at a distance equal to $2R$ ($R-$ radius of earth) from earth's surface. The minimum energy required to be given to the body so that it may escape out of earth's gravitational field will be
If $R$ is the radius of earth and $g$ is the acceleration due to gravity on the earth's surface. Then mean density of earth is ..........
What should be the angular speed of the earth, so that a body lying on the equator may appear weightlessness $(g = 10\,m/s^2, R = 6400\,km)$
An object is taken to height $2 R$ above the surface of earth, the increase in potential energy is $[R$ is radius of earth]