To make the frequency double of a spring oscillator, we have to

Three masses $700g, 500g$ and $400g$ are suspended at the end of a spring a shown  and are in equilibrium. When the $700g$ mass is removed, the system oscillates with a  period of $3\,seconds$, when the $500g$ mass is also removed, it will oscillate with a period of .... $s$

In the given figure, a body of mass $M$ is held between two massless springs, on a smooth inclined plane. The free ends of the springs are attached to firm supports. If each spring has spring constant $k,$ the frequency of oscillation of given body is :

Let $T_1$ and $T_2$ be the time periods of two springs $A$ and $B$ when a mass $m$ is suspended from them separately. Now both the springs are connected in parallel  and same mass $m$ is suspended with them. Now let $T$ be the time period in this position. Then

The length of a spring is $l$ and its force constant is $k$. When a weight $W$ is suspended from it, its length increases by $x$. If the spring is cut into two equal parts and put in parallel and the same weight $W$ is suspended from them, then the extension will be

Two particles $A$ and $B$ of equal masses are suspended from two massless springs of spring constants $K _{1}$ and $K _{2}$ respectively.If the maximum velocities during oscillations are equal, the ratio of the amplitude of $A$ and $B$ is