Two springs with spring constants {K₁} = 1500,N/m and {K₂} = 3000,N/m are stretched by same forc

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13.Oscillations

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Two springs with spring constants ${K_1} = 1500\,N/m$ and ${K_2} = 3000\,N/m$ are stretched by the same force. The ratio of potential energy stored in spring will be

A

$2:1$

B

$1:2$

C

$4:1$

D

$1:4$

Solution

(a) $U = \frac{{{F^2}}}{{2K}}$

$\Rightarrow U \propto \frac{1}{K}$

$\Rightarrow \frac{{{U_1}}}{{{U_2}}} = \frac{{{K_2}}}{{{K_1}}} = 2$

Standard 11

Physics

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