Gujarati
6.Permutation and Combination
easy

If $^{2n}{C_2}{:^n}{C_2} = 9:2$ and $^n{C_r} = 10$, then $r = $

A

$1$

B

$2$

C

$4$

D

$5$

Solution

(b) $\left( {\frac{{(2n)\;!}}{{2\;!\;(2n – 2)\;!}}} \right)\,\,2 = \left( {\frac{{n\;!}}{{2\;!(n – 2)\;!}}} \right)\,\,9$

$ \Rightarrow (2n)(2n – 1)2 = 9n(n – 1) \Rightarrow n = 5$

Now $^5{C_r} = 10 \Rightarrow r = 2$.

Standard 11
Mathematics

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