Two blocks $'A$' and $'B'$ each of mass $'m'$ are placed on a smooth horizontal surface. Two horizontal force $F$ and $2F$ are applied on the $2$ blocks $'A'$ and $'B'$ respectively as shown in figure. The block $A$ does not slide on block $B$. Then the normal reaction acting between the two blocks is
$F$
$F/2$
$\frac{F}{{\sqrt 3 }}$
$3\,F$
Arrangement of two block system is as shown. The net force acting on $1 \,kg$ and $2 \,kg$ blocks are (assuming the surfaces to be frictionless) respectively
Three identical blocks of masses $m=2\; k g$ are drawn by a force $F=10.2\; N$ with an acceleration of $0.6\; ms ^{-2}$ on a frictionless surface, then what is the tension (in $N$) in the string between the blocks $B$ and $C$?
What force should be applied on the wedge so that block over it does not move? (All surfaces are smooth)
A block of mass $m$ slides on the wooden wedge, which in turn slides backward on the horizontal surface. The acceleration of the block with respect to the wedge is : Given ${m}=8 \,{kg}, {M}=16\, {kg}$
Assume all the surfaces shown in the figure to be frictionless.
In the following figure, the object of mass $m$ is held at rest by a horizontal force as shown. The force exerted by the string on the block is